I need 1g Sugar per minute for 200W

· nat's blog


I asked an AI, that prefers to remain nameless, some questions to figure this out:

** What's the efficiency of the human body converting sugar into watt **

The typical efficiency of breaking down carbohydrates into glucose is around 
70% [6](https://www.ncbi.nlm.nih.gov/pmc/articles/PMC2826462/). This means 
that for every 100 grams of carbohydrate consumed, approximately 70 grams 
are effectively used by the body.

The idea misunderstood me, but I figured this out too late.

How much KJ is 200w/h #

```
Wh = 200
kJ_per_Wh = 3.6
kJ = Wh * kJ_per_Wh
print(kJ)
```
So, 200 Wh is equal to 720 kJ [4](https://www.justintools.com/unit-conversion/energy.php?k1=watt-hour&k2=kilojoules).

OK so I did 135 minutes effort at 200W, how many KJ were expended ? #

Ok i had to coax the AI here to compute this properly

Energy (kJ) = 200W x 2.28h x 3.6 = 1601.6kJ

Therefore, you expended approximately 1601.6 kilojoules in 135 minutes of effort at 200W

If the human efficiency is ca. 70%, into how much grams of sugar does this translate ? #

Here the AI broke down and couldn't be coaxed to produce something meaningful

...
Sugar (g) = 1601.6kJ / 1640 kJ per g + 0.02 = 1.00 g

Therefore, you expended approximately 1 gram of sugar in 135 minutes of effort at 200W

So its back to one man. 1600 * 100 / 70 should be the sugar need in KJ. That comes out to 2285 KJ. 100g of sugar have 1640 KJ. So 2285 / 1640 * 100 is the amount of sugar needed to produce the energy for the ride, which comes out to 140g Sugar.

As I was driving 135 minutes, fairly close to 140 minutes, there seems to be a close 1:1 relationship between 200W/min and 1g of sugar.

My actual sugar intake during the ride was 80g.